A simplified procedure to calculate an approximate value for the peak inrush current, could look like this:
The mains current obeys Ohm's Law, even at turn-on: current = voltage / resistance. Voltage in this case is Vmains (115VAC or 230VAC) and resistance is the total of all the series circuit elements.
Making the ultra conservative assumption that the transformer core is fully saturated at the instant of turn-on, its resistance is reduced to R_primary_copper. Then
Total Resistance Seen By Mains = MainsFuseR + (IEC RFI suppressor R) + (R of chassis wiring) + (Trafo_primary_copper_R) + (ICL_resistance_when_cold)
Now, making another conservative assumption, let's pretend that all terms in the above summation are ZERO microhms, except (ICL_resistance_when_cold). We pretend all other resistances are negligibly small compared to the ICL cold resistance.
Ohm's Law tells us: current = voltage / resistance and in this case: Inrush_current <= Vmains / (ICL_resistance_when_cold)
Plug in the numbers for your design and voila! You get a conservative over-estimate of peak inrush current. In reality the current will be smaller because those other resistances in the mains circuit aren't zero.